Giải câu 4 trang 9 VNEN toán 5 tập 1
Câu 4: Trang 9 VNEN toán 5 tập 1
Điền dấu < = >:
a. $\frac{3}{10}$ ... $\frac{7}{10}$ $\frac{5}{8}$ ... $\frac{3}{8}$ $\frac{25}{31}$ ... $\frac{19}{31}$
b. $\frac{7}{8}$ ... $\frac{5}{6}$ $\frac{2}{5}$ ... $\frac{3}{7}$ $\frac{1}{4}$ ... $\frac{1}{6}$
c. $\frac{2}{5}$ .... 1 $\frac{7}{6}$ ... 1 $\frac{21}{21}$ .... 1
d. $\frac{7}{6}$ ... $\frac{7}{3}$ $\frac{12}{17}$ ... $\frac{12}{13}$ $\frac{2}{3}$ ... $\frac{2}{5}$
a. $\frac{3}{10}$ < $\frac{7}{10}$ $\frac{5}{8}$ > $\frac{3}{8}$ $\frac{25}{31}$ > $\frac{19}{31}$
b. $\frac{7}{8}$ ... $\frac{5}{6}$
- $\frac{7}{8}$ = $\frac{21}{24}$; $\frac{5}{6}$ = $\frac{20}{24}$
- $\frac{21}{24}$ > $\frac{20}{24}$ => $\frac{7}{8}$ > $\frac{5}{6}$
$\frac{2}{5}$ ... $\frac{3}{7}$
- $\frac{2}{5}$ = $\frac{14}{35}$; $\frac{3}{7}$ = $\frac{15}{35}$
- $\frac{14}{35}$ < $\frac{15}{35}$ => $\frac{2}{5}$ < $\frac{3}{7}$
$\frac{1}{4}$ ... $\frac{1}{6}$
- $\frac{1}{4}$ = $\frac{3}{12}$; $\frac{1}{6}$ = $\frac{2}{12}$
- $\frac{3}{12}$ > $\frac{2}{12}$ => $\frac{1}{4}$ > $\frac{1}{6}$
c. $\frac{2}{5}$ .... 1
- 1 = $\frac{5}{5}$ mà $\frac{2}{5}$ < $\frac{5}{5}$ => $\frac{2}{5}$ < 1
$\frac{7}{6}$ ... 1
- 1 = $\frac{6}{6}$ mà $\frac{7}{6}$ > $\frac{6}{6}$ => $\frac{7}{6}$ > 1
$\frac{21}{21}$ = 1
d. $\frac{7}{6}$ < $\frac{7}{3}$ $\frac{12}{17}$ < $\frac{12}{13}$ $\frac{2}{3}$ > $\frac{2}{5}$
Bình luận