Giải câu 60 bài 8: Luyện tập sgk Toán 7 tập 1 Trang 31
Câu 60: trang 31 - sgk toán 7 tập 1
Tìm x trong các tỉ lệ thức sau:
a. $(\frac{1}{3}.x):\frac{2}{3}=1\frac{3}{4}:\frac{2}{5}$
b. $4,5:0,3=2,25:(0,1.x)$
c. $8:(\frac{1}{4}.x)=2:0,02$
d. $3:2\frac{1}{4}=\frac{3}{4}:(6.x)$
a. $(\frac{1}{3}.x):\frac{2}{3}=1\frac{3}{4}:\frac{2}{5}$
<=> $(\frac{1}{3}.x):\frac{2}{3}=\frac{7}{4}:\frac{2}{5}$
<=> $\frac{x}{3}:\frac{2}{3}=\frac{7}{4}.\frac{5}{2}$
<=> $\frac{x}{3}:\frac{2}{3}=\frac{35}{8}$
<=> $\frac{x}{3}=\frac{35}{8}.\frac{2}{3}$
<=> $\frac{x}{3}=\frac{35}{12}$
<=> $x.12=35.3$
<=> $x.12=105$
<=> $x=105:12=\frac{35}{4}$
Vậy $x=\frac{35}{4}$
b. $4,5:0,3=2,25:(0,1.x)$
<=> $\frac{9}{2}:\frac{3}{10}=\frac{9}{4}:\frac{1}{10}x$
<=> $\frac{9}{2}.\frac{10}{3}=\frac{9}{4}:\frac{1}{10}x$
<=> $15=\frac{9}{4}:\frac{1}{10}x$
<=> $\frac{1}{10}x=\frac{9}{4}:15$
<=> $\frac{1}{10}x=\frac{9}{4}:\frac{1}{15}$
<=> $\frac{1}{10}x=\frac{3}{20}$
<=> $x=\frac{3}{20}:\frac{1}{10}$
<=> $x=\frac{3}{20}.10$
<=> $x=\frac{3}{2}$
Vậy $x=\frac{3}{2}$.
c. $8:(\frac{1}{4}.x)=2:0,02$
<=> $8:(\frac{1}{4}.x)=2:\frac{2}{100}$
<=> $8:(\frac{1}{4}.x)=100$
<=> $\frac{1}{4}.x=8:100$
<=> $\frac{1}{4}.x=\frac{2}{25}$
<=> $x=\frac{2}{25}:\frac{1}{4}$
<=> $x=\frac{2}{25}.4$
<=> $x=\frac{8}{25}$
Vậy $x=\frac{8}{25}$.
d. $3:2\frac{1}{4}=\frac{3}{4}:(6.x)$
<=> $3:\frac{9}{4}=\frac{3}{4}:(6.x)$
<=> $\frac{4}{3}=\frac{3}{4}:(6.x)$
<=> $6.x=\frac{3}{4}:\frac{4}{3}$
<=> $6.x=\frac{9}{16}$
<=> $x=\frac{9}{16}:6$
<=> $x=\frac{9}{16}:\frac{1}{6}$
<=> $x=\frac{3}{32}$
Vậy $x=\frac{3}{32}$.
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