Giải SBT hóa 11: bài tập 9.36 trang 70

(1) \(C{H_2} = C{H_2} + HCl\) $ \overset{xt}{\rightarrow}$ \(C{H_3} - C{H_2} - Cl\)

(2) \({C_2}{H_5}Cl + NaOH\) $\overset{ancol}{\rightarrow}$ \(C{H_2} = C{H_2} + NaCl + {H_2}O\)

(3) \({C_2}{H_5}Cl + NaOH\) $ \overset{nuoc}{\rightarrow}$ \({C_2}{H_5}OH + NaCl\)

(4) \({C_2}{H_5}OH + HCl\) $ \overset{t^{o}}{\rightarrow}$ \({C_2}{H_5}Cl + {H_2}O\)

(5) \({C_2}{H_4} + {H_2}O\) $ \overset{H^{+}}{\rightarrow}$ \({C_2}{H_5}OH\)

(6) \({C_2}{H_5}OH\) $ \overset{H_2SO_4, 170^{o}C}{\rightarrow}$ \({C_2}{H_4} + {H_2}O\)

(7) \({C_2}{H_5}OH + CuO\) $ \overset{t^{o}}{\rightarrow}$ \(C{H_3}CHO + Cu + {H_2}O\)

(8) \(C{H_3}CHO + {H_2}\) $ \overset{Ni, t^{o}}{\rightarrow}$ \({C_2}{H_5}OH\)

(9) \({C_2}{H_5}OH + {O_2}\) $ \overset{xt}{\rightarrow}$ \(C{H_3}COOH + {H_2}O\)

(10) 2\(C{H_3}CHO + {O_2}\) $ \overset{xt}{\rightarrow}$ 2\(C{H_3}COOH\)

(11) \(C{H_3}COOH + NaOH \to \) \(C{H_3}COONa + {H_2}O\)

(12) \(C{H_3}COONa + {H_2}S{O_4}\) \( \to C{H_3}COOH + NaHS{O_4}\)

(13) \(C{H_3}COOH + {C_2}{H_5}OH\) $ \rightleftharpoons $(H₂SO₄đ, t^o) \(C{H_3}COO{C_2}{H_5} + {H_2}O\)

(14) \(C{H_3}COO{C_2}{H_5} + {H_2}O\) $ \rightleftharpoons $ (H⁺) \(C{H_3}COOH + {C_2}{H_5}OH\)

(15) \(C{H_3}COO{C_2}{H_5} + NaOH\) $ \overset{t^{o}}{\rightarrow}$ \(C{H_3}COONa + {C_2}{H_5}OH\)