Giải câu 2 trang 10 VBT toán 5 tập 1

Câu 2: Trang 10 VBT toán 5 tập 1

Tính (theo mẫu):

Mẫu: $\frac{9}{10}$ x $\frac{9}{10}$ = $\frac{9\times 5}{10\times 6}$ = $\frac{3\times \not{3}\times \not{5}}{\not{5}\times 2\times \not{3}\times 2}$ = $\frac{3}{4}$

a) $\frac{9}{22}$ x $\frac{33}{18}$ = .......................

b) $\frac{12}{35}$ : $\frac{36}{25}$ = ........................

c) $\frac{19}{17}$ : $\frac{76}{51}$ = .........................


a) $\frac{9}{22}$ x $\frac{33}{18}$ = $\frac{9\times 33}{22\times 18}$ = $\frac{\not{9}\times \not{11}\times 3}{\not{11}\times 2\times \not{9}\times 2}$ = $\frac{3}{4}$

b) $\frac{12}{35}$ : $\frac{36}{25}$ = $\frac{12}{35}$ x $\frac{25}{36}$ = $\frac{12\times 36}{25\times 35}$= $\frac{\not{12}\times \not{5}\times 5}{\not{5}\times 7\times \not{12}\times 3}$ = $\frac{5}{21}$

c) $\frac{19}{17}$ : $\frac{76}{51}$ = $\frac{19}{17}$ x $\frac{51}{76}$ = $\frac{19\times 51}{17\times 76}$ = $\frac{\not{19}\times \not{17}\times 3}{\not{17}\times \not{19}\times 4}$ = $\frac{3}{4}$


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